If a star is measured as shifting 0.6 arc seconds in a three month period, as viewed from the earth...? - arc shift knob
When a star as measured by the change of 0.6 arcseconds over a period of three months, in view of the earth for years, like the light?


2 comments:
You determine your distance from the change in parallax.
D = 1 / p
So:
Corresponds to 1/0.6 (rounded) 1.7 parsecs.
1 parsec = 3.26 light-years, so ...
The star is about 5542 years light.
My hypothesis is that the parallax due to the movement of the earth around the orbit of the DOM 3 months of this distance corresponds to approximately:
93E6 miles km x sqrt (2) = 132 million.
132 miles E6 / invTAN (0.6 arcsec) = 45E12 miles, about 7.7 light years.
The value of 5.4 years and found that LT is assumed that the star more or less parallel to the orbit of the earth. This is also true. My calculations would assume that the star is tangential to the orbit of the earth, so that the sqrt (2) The difference in the two responses.
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